(3x^2-35x+72)/(x-9)

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Solution for (3x^2-35x+72)/(x-9) equation: 


D( x )

x-9 = 0

x-9 = 0

x-9 = 0

x-9 = 0 // + 9

x = 9

x in (-oo:9) U (9:+oo)

(3*x^2-(35*x)+72)/(x-9) = 0

(3*x^2-35*x+72)/(x-9) = 0

3*x^2-35*x+72 = 0

3*x^2-35*x+72 = 0

DELTA = (-35)^2-(3*4*72)

DELTA = 361

DELTA > 0

x = (361^(1/2)+35)/(2*3) or x = (35-361^(1/2))/(2*3)

x = 9 or x = 8/3

(x-8/3)*(x-9) = 0

x-8/3 = 0

x-8/3 = 0 // + 8/3

x = 8/3

x = 8/3

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